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Solutions to HackerRank Coding Challenges in Python Solutions to HackerRank Coding Challenges in Python | Jamie Lu - Data Analytics Design & Visualization

Solutions to HackerRank Coding Challenges in Python

One of the best ways to absorb and retain new concepts that I have learnt about coding in Python is through documentation! As part of my journey to future-proof my data career and also to improve my proficiency in the python language, I have spent some of my free time to solve coding challenges on HackerRank. In this blog post, I shared the solutions to some of the practice challenges which I have completed and successfully passed the code in the compiler on HackerRank. Do click on Read More or the title of this blog post for the Python 3 solutions which I have created.

Python Introduction (Easy) Questions

If-Else

Task

Given an integer, n , perform the following conditional actions:

  • If n is odd, print Weird
  • If n is even and in the inclusive range of 2 to 5, print Not Weird
  • If n is even and in the inclusive range of 6 to 20, print Weird
  • If n is even and greater than 20, print Not Weird

Input Format: A single line containing a positive integer, n.

Constraints:

  • 1 <= n <= 100

Output Format: Print Weird if the number is weird. Otherwise, print Not Weird.

Solution:

#!/bin/python3

import math
import os
import random
import re
import sys



if __name__ == '__main__':
    n = int(input().strip())
    # First we use modulus % operator to find the odd numbers and label them as 'Weird'. Odd numbers will return a remainder that is not zero.
    if n%2 != 0:
        print("Weird")
    # Next we find the criteria for the rest of the integer as stated
    else :
        if(n>=2 and n<=5):
            print("Not Weird")
        elif(n>=6 and n<=20):
            print("Weird")
        elif(n>20):
            print("Not Weird")
    

Arithmetic Operators

Task

The provided code stub reads two integers from STDIN, a and b . Add code to print three lines where:

  1. The first line contains the sum of the two numbers.
  2. The second line contains the difference of the two numbers (first - second).
  3. The third line contains the product of the two numbers.

Example:

a = 3

b = 5

Print the following:

8
-2
15

Input Format: The first line contains the first integer, a. The second line contains the second integer, b.

Output Format: Print the three lines as explained above.

Sample Input 0

3
2

Sample Output 0

5
1
6

Solution:

if __name__ == '__main__':
    a = int(input())
    b = int(input())
    
    print(a + b)
    print(a - b)
    print(a * b)

Division

Task

The provided code stub reads two integers from STDIN, a and b . Add logic to print two lines. The first line should contain the result of integer division, a//b . The second line should contain the result of float division, a/b .

No rounding or formatting is necessary.

Example:

a = 3

b = 5

  • The result of the integer division 3//5 = 0.
  • The result of the float division is 3/5 = 0.6.

Print:

0
0.6

Input Format

The first line contains the first integer, a . The second line contains the second integer, b .

Output Format

Print the two lines as described above.

Solution:

if __name__ == '__main__':
    a = int(input())
    b = int(input())
    
    print(a//b)
    print(a/b)

Loops

Task

The provided code stub reads and integer,n, from STDIN. For all non-negative integers i < n , print i**2.

Example

n = 3

The list of non-negative integers that are less than n = 3 is [0,1,2] . Print the square of each number on a separate line.

0
1
4

Input Format: The first and only line contains the integer, n.

Constraints: 1 <= n <= 20

Output Format: Print n lines, one corresponding to each i.

Sample Input 0

5

Sample Output 0

0
1
4
9
16

Solution:

if __name__ == '__main__':
    n = int(input())

for i in range(n):
    print (i ** 2)

The included code stub will read an integer,n , from STDIN.

Without using any string methods, try to print the following: 123 . . . n

Note that “…” represents the consecutive values in between.

Example n=5

Print the string 12345.

Input Format: The first line contains an integer n .

Constraints: 1 <= n <= 150

Output Format: Print the list of integers from 1 through n as a string, without spaces.

Sample Input 0

3

Sample Output 0

123

Solution:

if __name__ == '__main__':
    n = int(input())
    
for i in range(1, n+1):
    print(i, end = '')
    
    #In Python 3, end =' ' appends space instead of newline.

Python Introduction (Medium) Questions

Write a function

An extra day is added to the calendar almost every four years as February 29, and the day is called a leap day. It corrects the calendar for the fact that our planet takes approximately 365.25 days to orbit the sun. A leap year contains a leap day.

In the Gregorian calendar, three conditions are used to identify leap years:

  • The year can be evenly divided by 4, is a leap year, unless:
    • The year can be evenly divided by 100, it is NOT a leap year, unless:
    • The year is also evenly divisible by 400. Then it is a leap year. This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years.

Task

Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False.

Note that the code stub provided reads from STDIN and passes arguments to the is_leap function. It is only necessary to complete the is_leap function.

Input Format: Read year , the year to test.

Constraints

1900 <= year <= 10 ** 5

Output Format: The function must return a Boolean value (True/False). Output is handled by the provided code stub.

Sample Input 0

1990

Sample Output 0

False

Explanation 0

1990 is not a multiple of 4 hence it’s not a leap year.

Solution:

def is_leap(year):
    leap = False
    
    if(year % 400 == 0): 
        leap = True
    elif(year % 4 == 0 and year % 100 != 0):
        leap = True
    
    return leap

    #def name(arguments) is used to create a function be sure to have a return type. 
    
year = int(input())
print(is_leap(year))